A3.00 kg object is moving in the xy plane, with its x and y coordinates given by x = 5t³ ! 1 and y = 3t ² + 2, where x and y are in meters and t is in seconds. find the magnitude of the net force acting on this object at t = 2.00 s.

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of

Coordinate of position of

Time = 2.00 s

We need to calculate the acceleration

For x coordinates

On differentiate w.r.to t

On differentiate again w.r.to t

The acceleration in x axis at 2 sec

For y coordinates

On differentiate w.r.to t

On differentiate again w.r.to t

The acceleration in y axis at 2 sec

The acceleration is

We need to calculate the net force

The magnitude of the force

Hence, The net force acting on this object is 180.89 N.

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