A43 v battery charges a 4750 pf air gap capacitor. after disconnecting. porcelain (k-7) is placed between the plates. what is the resulting charge of the plates? o 154 hc o 144 ac o 1.73 hc o 1.23 ac s

1.2255 × 10⁻⁶ μC

Explanation:

Given

Capacitance, C = 4750 pF = 4750×10⁻¹² F

Potential difference, V = 43 V

Relative permittivity of the dielectric, k = 7

now we know

charge Q = CV

⇒Q = 4750×10⁻¹² × 43 = 2.0425 × 10⁻⁷ C

Now, the charge (Q') due to the placing of the dielectric in between the gap

Q' = C'V

where,

C' = kC = 7 ×  4750×10⁻¹² = 33250 × 10⁻¹² F

substituting the C' in Q'

we get

Q' = 33250 × 10⁻¹² × 43 = 1.42975 × 10⁻⁶ C

Thus,

Resulting charge will be = Q' - Q

⇒Resulting charge = 1.42975 × 10⁻⁶ C - 2.0425 × 10⁻⁷ C = 1.2255 × 10⁻⁶ C

Resulting charge =1.2255 × 10⁻⁶ μC

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation: