Aboxcar of length 10.1 m and height 2.4 m is at rest on frictionless rails. inside the boxcar (whose mass when empty is 3500 kg) a tank containing 1500 kg of water is located at the left end. the tank is 1.1 m long and 2.4 m tall. at some point the walls of the tank start to leak, and the water fills the floor of the boxcar uniformly. assume that all the water stays in the boxcar. after all the water has leaked out what will be the final velocity of the boxcar? (take movement to the right as positive. assume that the mass of the boxcar is evenly distributed.)

Ineed the problem dude

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j