Adiait consists of a dhree 60.0 kq resistors in paralled placed in series with a 10.0 resisaor 7. a circuit consists three 60.0 kω resistors in parallel placed in series a and a 6.00 v battery. a) draw the circuit, using correct circuit symbols. b) find the equivalent resstance of the circuit. c) find the current in the 100.0 kq resistor. d) find the voltage across one of the 60.0 kq resistors.

(a): The circuit is attached.

(b):  The equivalent resistance is Req= 120 kΩ

(c): The current in the 100 kΩ Resistor is I= 5 * 10⁻⁵ A.

(d): The voltage across one of the 60 kΩ resistor is V= 1 V

Explanation:

Req= {(1/60kΩ)*3}⁻¹+100kΩ

Req= 120 kΩ (b)

I= V/Req

I= 5* 10⁻⁵ A (c)

V= I * 20kΩ

V= 1 V  (d)

car a and b are moving in opposite directions

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