An object is attached to a spring, the spring is stretched by 23.7 cm in the negative direction, and the object is released, oscillating in simple harmonic motion. after 0.317 s, it is again 23.7 cm from the equilibrium position, having passed through the equilibrium position once in those 0.317 s. determine the speed of the object after 1.39 seconds. number cm/s

83.17 cm/s

Explanation:

Let positive x be negative direction and negative x be positive direction in this question

General equation of motion of SHM is

x= --------1

where is natural frequency of motion given by

=

Where K is spring constant

here A=23.7cm

And it is given it is again at 23.7 from equilibrium position having passed through the equilibrium once.

i.e. it covers this distance in sec

where T is the time period of oscillation i.e. returning to same place after T sec

therefore T=0.634 sec

differentiating equation 1 we get

v=cos

and =

=9.911rad/s

=

v=83.17 cm/s

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation:

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is