Ablock of ice with a mass of 2.50 kg is moving on a frictionless, horizontal surface. at time t = 0, the block is moving to the right with a velocity of magnitude 8.00 m/s. calculate the velocity of the block after a force of 7.00 n directed to the left has been applied for 5.00 s.

The velocity of the block is 22 m/s.

Explanation:

Given that,

Mass = 2.50 kg

Velocity = 8 .00 m/s

Force = 7.00 N

Time t = 5.00

We need to calculate the change in velocity it means acceleration

Using newton's law

Where,

m = mass

a = acceleration

Put the value into the formula

We need to calculate the velocity of the block

Using equation of motion

Where,

v = final velocity

u = initial velocity

a = acceleration

t =time

Put the value in the equation

Hence, The velocity of the block is 22 m/s.