At the bottom of a loop in the vertical (r, θ) plane at an altitude of 575 m, the airplane p has a horizontal velocity of 665 km/h and no horizontal acceleration. the radius of curvature of the loop is 1210 m. for the radar tracking at o, determine the recorded values of r¨ and θ¨ for this instant.

This is what i found “in a gas turbine engine, the combustor or combustion chamber is fed high pressure air by the compression system. early gas turbine engines used a single chamber known as a can type combustor. today three main configurations exist: can, annular and cannular (also referred to as can-annular tubo-annular).” i hope this you for what your looking for. can you plz mark me brainliest?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s