Aladder 10 ft long rests against a vertical wall. if the bottom of the ladder slides away from the wall at a rate of 1.2 ft/s, how fast is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall? (that is, find the angle's rate of change when the bottom of the ladder is 8 ft from the wall.) rad/s

0.2 rad/s

Explanation:

Given data

Velocity of the bottom point of the ladder=1.2Ft/s

Length of ladder=10ft

distance of the bottom most point of ladder from origin=8ft

From the data the angle θ with ladder makes with horizontal surface is

Cosθ=

θ=36.86≈37°

We have to find rate of change of θ

From figure we can say that

+=

Differentiating above equation we get

=-

i.e

ω=0.2rad/s

i.e.Rate of change of angle=0.2 rad/s

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

. west