A12.0 kg block rests on an inclined plane. the plane makes an angle of 31.0° with the horizontal, and the coefficient of friction between the block and the plane is 0.158. the 12.0 kg block is tied to a second block (mass = 38.0 kg) which hangs over the end of the inclined plane after the rope passes over an ideal pulley. (a) what is the acceleration of each of the two blocks, and (b) what is the tension in the rope?

The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

Explanation:

Given that,

Mass = 12.0 kg

Angle = 31.0°

Friction coefficient = 0.158

Mass of second block = 38.0 kg

Using formula of frictional force

....(I)

Where, N = normal force

Put the value of N into the formula

Put the value of N in equation (I)

Now, Weight of second block

The horizontal force is

....(II)

(I). We need to calculate the acceleration

(II). We need to calculate the tension in the rope

Hence, The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

answer: strength i guess

explanation:

e) none of the above answers are correct