Aconducting sphere of radius 20.0 cm carries an excess charge of +15.0 µc, and no other charges are present. (k = 1/4π ε0 = 8.99 × 109 n · m2/c2) the potential (relative to infinity) due to this sphere at a point 12.0 cm from its center is closest to a conducting sphere of radius 20.0 cm carries an excess charge of +15.0 µc, and no other charges are present. ( = 1/4π = 8.99 × 109 n · m2/c2) the potential (relative to infinity) due to this sphere at a point 12.0 cm from its center is closest to 674 kv. 1130 kv. 3380 kv. zero. 9380 kv.

Ihave no idea sorry

Domain eukarya; kingdom plantae should be the answer.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Wow good luck with that answer