Afire hose ejects a stream of water at an angle of 35.0â° above the horizontal. the water leaves the nozzle with a speed of 25.0 m/s. assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

The fire hose be located 59.80 m away to hit the highest possible fire.

Explanation:

Vertical velocity = 25 sin35 = 14.34 m/s

Acceleration = -9.81m/s²

At maximum height , final vertical velocity = 0 m/s

We have v = u + at

Substituting

           0 = 14.34 - 9.81 x t

           t = 1.46 s

Time of flight of water = 2 x 1.46 = 2.92 s

Horizontal velocity = 25 cos35 = 20.48 m/s

Horizontal displacement = 20.48 x 2.92 = 59.80 m

So, the fire hose be located 59.80 m away to hit the highest possible fire.

none, its a machine

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards