Aparticle is located on the x axis 4.9 m from the origin. a force of 38 n, directed 30° above the x axis in the x-y plane, acts on the particle. what is the torque about the origin on the particle? round your answer to the nearest whole number. use a minus sign to indicate a negative direction and no sign to indicate a positive direction.

Torque is 93 Nm anticlockwise.

Explanation:

We have value of torque is cross product of position vector and force vector.

A force of 38 N, directed 30° above the x axis in the x-y plane.

        Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j

A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.

Position vector, r = 4.9 i

Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm

So Torque is 93 Nm anticlockwise.

the total distance traveled by the car is

30km + 49km = 79 km .

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!