Acircular loop of radius 0.7cm has 520 turns of wire and carries a current of 3.9a. the axis of the loop makes an angle of 57 degrees with a magnetic field of 0.982t. find the magnitude of the torque on the loop.

Torque,

Explanation:

It is given that,

Radius of the circular loop, r = 0.7 cm = 0.007 m

Number of turns, N = 520

Current in the loop, I = 3.9 A

The axis of the loop makes an angle of 57 degrees with a magnetic field.

Magnetic field, B = 0.982 T

We need to find the magnitude of torque on the loop. It is given by :

So, the magnitude of torque is 0.1669 N-m. Hence, this is the required solution.