Apump lifts water from a lake to a large tank 20 m above the lake. how much work against gravity does the pump do as it transfers 5.0 m^3 if the density is ? =1000kg/m^3?

The work done by the pump against gravity in transfering 5 m³ of water to a tank 20 m above the lake is 980000 J

We'll begin by calculating the mass of the water. This can be obtained as follow:

Volume of water = 5 m³

Density of water = 1000 Kg/m³

Mass = Density × Volume

Mass of water = 1000 × 5

Mass of water (m) = 5000 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 9.8 m/s²

Work done = mgh

Work done = 5000 × 9.8 × 20

Thus, the work done by the pump is 980000 J

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980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

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hello there!

your answer is a “generator”

a generator does not create energy but instead it transforms it.

it’s basically a motor working in reverse.