Sand falls from an overhead bin and accumulates in a conical pile with a radius that is always twotwo times its height. suppose the height of the pile increases at a rate of 33 cm divided by scm/s when the pile is 1010 cm high. at what rate is the sand leaving the bin at that instant?

-423 m³/s

Explanation:

Volume of a cone is:

V = ⅓ π r² h

Given r = 2h:

V = ⅓ π (2h)² h

V = ⁴/₃ π h³

Taking derivative with respect to time:

dV/dt = 4π h² dh/dt

Given h = 1010 cm and dh/dt = 33 cm/s:

dV/dt = 4π (1010 cm)² (33 cm/s)

dV/dt ≈ 4.23×10⁸ cm³/s

dV/dt ≈ 423 m³/s

The pile is growing at 423 m³/s, so the bin is draining at -423 m³/s.

i think the answer would be reserve.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)