Acarnot refrigerator operating between -30.0 ∘c and + 40.0 ∘c extracts heat from the cold reservoir at the rate 300 j/s . what are (a) the coefficient of performance of this refrigerator, (b) the rate at which work is done on the refrigerator and (c) the rate at which heat is exhausted to the hot side?

The co-efficient of performance of a refrigerator is the ratio of heat removed from the cold reservoir to the work done: COP = Q c W = Q c Q h − Q c = Q c / Q h 1 − Q c / Q h COP=QcW=QcQh−Qc=Qc/Qh1−Qc/Qh So W = Qc/COP. Since it is a Carnot cycle: Qc/Qh = Tc/Th To find Qh use W = Qh-Qc

Reference https://www.physicsforums.com/threads/carnot-refrigerator-coefficient-of-performance.145848/

Explanation:

divide the right side by the left side

0.024÷1.2=0.02 for example