Aheavy boy and a lightweight girl are balanced on a massless seesaw. if they both move forward so that they are one-half their original distance from the pivot point, what will happen to the seesaw? assume that both people are small enough compared to the length of the seesaw to be thought of as point masses. g

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Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

The answer is frictional force