An object moving in a straight line changes its velocity uniformly from 2m/s to 4 m/s over a distance of 12 m. what was its acceleration? (a) 0.5 m/s^2 (b) 1 m/s^2 (c) 2 m/s^2 (d) 3 m/s^2

A

Explanation:

Initial velocity, u = 2m/s

Final velocity, v = 4m/s

Distance covered, s = 12m

Acceleration, a = ?

Using

v² = u² + 2as

2as = v² - u²

a = v²-u²/2s

a = 4²-2²/2 x 12

a = 16-4/24

a = 12/24

a = 0.5m/s²

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get