Awoman walks 237 m in the direction 27.2 east of north, then 335 m directly east. find the difference between the distance the woman walks and the magnitude of her displacement. (answer in m.)

81.1 m

Explanation:

X = 237 m 27.2 east of north 237 (Sin27.2 i + Cos 27.2 j)

X = 108.33 i + 210.8 j

Y = 335 east = 335 i

Displacement = X + Y = 108.33 i + 210.8 j + 335 i = 443.33 i + 210.8 j

(magnitude of displacement)^2 = 443.33^2 + 210.8^2

magnitude of displacement = 490.9 m

Distance traveled = 237 + 335 = 572 m

Difference in the magnitude of displacement and distance = 572 - 490.9

                                                                                                   = 81.1 m

0.11 m/s and 0.28 m/s should be correct