An object is subject to the potential v(x) = ae-x/b. it starts at position x = 0 with an initial kinetic energy t0. a is a positive number.
i found the force f(x) to be (a/b)e-x/b and found the equilibrium positions do not exist because ln 0 is undefined. i calculated the turning point to be x = -(b/ln(e/
how do i sketch v(x) and total energy, e?
how do i sketch f(x)?
how would i then describe the motion of the object?
since the equilibrium position doesn't exist, wouldn't that mean the object continues moving forever?

11. you want to calculate the displacement of an object thrown over a bridge. using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before hitting the water?

Did the proton move into a region of higher potential or lower potential? did the proton move into a region of higher potential or lower potential? because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential. because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential. because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. request answerpart bwhat was the potential difference that stopped the proton? express your answer with the appropriate units.î”v î” v = nothingnothingrequest answerpart cwhat was the initial kinetic energy of the proton, in electron volts? express your answer in electron volts. ki k i = nothing ev request answerprovide feedback

The x-coordinate of a particle in curvilinear motion is given by x = 3.1t3 - 4.9t where x is in feet and t is in seconds. the y-component of acceleration in feet per second squared is given by ay = 2.3t. if the particle has y-components y = 0 and vy = 5.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 1.8 sec. sketch the path for the first 1.8 seconds of motion, and show the velocity and acceleration vectors for t = 1.8 sec. answers: v = ft/sec a = ft/sec2