Physics
Physics, 27.06.2019 00:40, mikeydog3781

The intensity of sunlight under the clear sky is 920 w/m2 . how much electromagnetic energy is contained per cubic meter near the earth’s surface? the speed of light is 2.99792 × 108 m/s. answer in units of j/m 3 .

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Physics, 26.07.2019 23:20, dndndndnxmnc
When light falls on a perfect absorbing surface (i.e. a surface the completely absorbs all the light), the amount of momentum transferred in a tune delta t is given by delta p = ac delta t where a is the surface area illuminated, c is the velocity of light, and is the momentum density earned by the electromagnetic wave which from class you may remember was given by where the intensity is given by = 1/c^2 i where the intensity is given by i = |s| where s is the poynting vectore. the pressure p (force per unit area) is defined as the amount of momentum transferred to the material per unit area per unit time. in other words, p = 1/a delta p/delta t = i/c the above equation lets you calculate the "radiation pressure" for an electromagnetic field. the intensity of sunlight hitting the earth is about 1300 w/m^2. if sunlight strikes a perfect absorber, calculate the pressure it absorbs? now repeat the calculation above for a perfect reflector. for each case, calculate the fraction of atmospheric pressure this corresponds to.
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Biology, 02.10.2019 11:30, kathiewallentin1767
Which explains how sunlight warms the earth? a. the earth''s atmosphere absorbs electromagnetic radiation and heats up. b. the earth''s surface absorbs electromagnetic radiation from the sun and warms the earth. c. the earth''s atmosphere releases electromagnetic radiation, thereby causing the surface to warm. d. as electromagnetic radiation hits the surface and bounces off, it transfers heat energy to the surface.
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Physics, 22.11.2019 22:31, mahhvelousg97
The power emitted by the sun in the form of electromagnetic waves is about 4.00 1026 w. the distance from the earth to the sun is about 150 million km, and the radius of the earth is approximately 6400 km. (a) using these numbers, determine the intensity of sunlight reaching earth. w/m2 (b) using these numbers, determine the total energy every second in the sunlight that is incident on the earth. for reference, on your electricity bill, you get charged about $1 for every 3.6 107 j of electricity you use, so you might want to think about the value of one second's worth of sunlight hitting the earth
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