Acar is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. what is the distance covered before the car comes to a stop? (round your answer to one decimal place.) ft

The distance covered by car before stopping is 61.13 ft.

Explanation:

Given data:

Initial Speed of car is, .

Deceleration of car is, . (Negative sign shows negative acceleration)

Applying the second kinematic equation of motion as,

Here, s is the distance covered and v is the final speed. Since, car stops finally, v = 0.

Solving as,

Thus, distance covered by car before stopping is 61.1 ft.

For more details, refer to the link:

link

Distance, d = 61.13 ft

Explanation:

It is given that,

Initial speed of the car, u = 50 mi/h = 73.34 ft/s

Finally, it stops i.e. v = 0

Deceleration of the car,

We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :

s = 61.13 ft

So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.

the answer would be   dignified - apex