Arigid tank contains 1 kg of air (ideal gas) at 15 °c and 210 kpa. a paddle wheel supplies work input to the air such that final temperature is 97 "c. the specific heats are cp 1.005 kj(kg. k) and c-0.718 kj/(kg. k). determine the total work done in kj:

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft