If 2.0 x 10^-4 c charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?
4.0 x 10^-1 a
1.0 x 10^2 a
1.0 x 10^-10 a
4.0 x 10^0 a

Q= I×t

Where Q is charge in Coulombs C,

I is current in Amperes A,

t is in seconds s.

The rate of current flow is defined as the charge passing through a point in the circuit per second.

Rearranging formula gives I=

⇒I = = 4 Amperes

∴ current flow = 4.0×10^0 A

glen is correct.

step-by-step explanation:

glen is correct because when you multiply 4 * 2 = 8.

and 4 * 3 = 12.

the bal will not change its velocity.