Answers: 2
= mass of water = 50 g
= specific heat of water = 4.186 J/(g °C)
= Initial temperature of water = 22.00 °C
= mass of alloy = 25 g
= specific heat of alloy = ?
= Initial temperature of alloy = 93.00 °C
= Final equilibrium temperature = 31.10 °C
= 
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A25.0−gsample of an alloy at 93.00°cis placed into 50.0 gof water at 22.00°cin an insulated coffee-c...
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