Amarble is dropped from a toy drone that is 25 m above the ground, and slowly rising with a vertical velocity of 0.8 m/s. how long does it take the marble to reach the ground?

2.18 s

Explanation:

H = - 25 m ( downwards)

U = - 0.8 m/s

g = - 9.8 m/s^2

Let time taken is t.

Use second equation of motion

H = u t + 1/2 g t^2

- 25 = - 0.8 t - 1/2 × 9.8 × t^2

4.9 t^2 + 0.8 t - 25 = 0

By solving we get

t = 2.18 s

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