Find the amount of heat conducted per second through a bar of aluminum if the cross sectional area is 30 cm the length of the bar is 1.5 m and one of the ends has a temperature of 25°c and the other has a temperature of 300°c. thermal conductivity of aluminum is 1.76 x 10^4 cal cm / m^2 h°c convert the units as needed

9680 cal

Explanation:

A = cross-sectional area of the bar = 30 cm² = 30 x 10⁻⁴ m²

L = length of the bar = 1.5 m

T₁ = Temperature at one end of the bar = 25 °C

T₂ = Temperature at other end of the bar = 300 °C

k = Thermal conductivity of Aluminum = 1.76 x 10⁴ Cal cm /(m² ⁰C)

Q = amount of heat conducted per second

Amount of heat conducted per second is given as

Q = (1.76 x 10⁴) (30 x 10⁻⁴) (300 - 25)/1.5

Q = 9680 cal

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