A2.00-m long piano wire with a mass per unit length of 12.0 g/m is under a tension of 8.00 kn. what is the frequency of the fundamental mode of vibration of this wire?

204.1 Hz

Explanation:

The fundamental frequency of a vibrating string is given by:

where

L is the length of the string

T is the tension in the string

is the linear mass density of the string

For the wire in this problem, we have

L = 2.00 m

T = 8.00 kN = 8000 N

Therefore, substituting into the equation, we find the frequency of the string:

we need to know the time interval during which the force acts. impulse of force = momentum change