Heidi and heather take a 30 minute walk eastward along a straight road to a store 2.0 km away. what is their average velocity in m/s?

Average velocity =

(distance and direction of their change in location)

divided by

(time for the change) .

Distance and direction of their change in location = 2.0 km east  (their "displacement")

Time for the change = 30 minutes

Average velocity = (2.0 km east) / (30 minutes)

Average velocity = (2/30) (km east/minute)

Average velocity = 0.067 km/min east

or

Average velocity = 4.0 km/hr east

Just to be difficult, the question specifies that the answer must be given in units of m/s.  Is no problema for nosotros:

Average velocity = (4.0 km-east/hour) x (1,000 m/km) x (1 hour/3600 sec)

Average velocity = (4 x 1,000 / 3,600) (km-east-meter-hr / hr-km-sec)

Average velocity = 1.111... m/s East

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min