A11 kg mass on a frictionless inclined surface is connected to a 2.1 kg mass. the pulley is massless and frictionless, and the connecting string is massless and does not stretch. the 2.1 kg mass is acted upon by an upward force of 6.6 n, and thus has a downward acceleration of only 3.6 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the tension in the connecting string?

6.4 N

Explanation:

Draw free body diagrams for each mass.

For the mass on the inclined surface, the sum of forces parallel to the incline are:

∑F = ma

T - Mg sin θ = Ma

For the hanging mass, the sum of the forces in the y direction are:

∑F = ma

T - mg + F = m(-a)

We're given that g = 9.8 m/s², M = 11 kg, m = 2.1 kg, F = 6.6 N, and a = 3.6 m/s².

From the second equation, we have everything we need to find the tension force.

T - (2.1)(9.8) + 6.6 = (2.1)(-3.6)

T = 6.42 N

Rounded to 2 sig figs, the tension is 6.4 N.

v 154.9= 0.9 length length s little over 154.9cm