(100 points)some air filters contain a small component that maintains a constant negative chargeq. particlesnear this component are attracted through the coulomb force. consider a single, neutral, particle a distancedfrom the air filter component. the distancedis much larger than the size of the particle. a carbon atom in theparticle has polarizabilityα.a. calculate the magnitude of the electric force on an atom in the particle. explain your steps clearly and payparticular attention to defining any additional algebraic symbols so that we can follow your reasoning. ifyou make an assumption state them explicitly. b. why can you neglect the effects of gravity in your calculation? c. if the particle was initially twice as far from the charged component, how would the electric force on theparticle change? d. if the mass of the particle was doubled, how would the electric force on the particle change? e. if the charge on the air filterqhad been positive instead of negative, how would the electric force on theparticle change? would anything about this problem change?

That depends on what kind of environ meant it is in  in space it has the same force that was applied when the velocity was gained

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s