Atesla roadster car accelerates from rest at a rate of 7 m /s^2 for a time of 3.9 s calculate the distance it travels in time.

Accelerating from rest at the rate of 7 m/s^2 for 3.9 s ...

D= 1/2 a t^2

D= (3.5) (3.9)^2

D= 53.2 m

The car travels 53.2 meters in space, and 3.9 seconds in tme.

the answer would be   dignified - apex