Acar of 1000 kg with good tires on a dry road can decelerate (slow down) at a steady rate of about 5.0 m/s2 when braking. if a car is initially traveling at 20 m/s (45 mi/h), (a) how much time does it take the car to stop? (b) what is its stopping distance? (c) what is the deacceleration? (d) how big is the net force to be applied to stop this car? (e) calculate the work done by this force (work = force * distance). (f) during the stopping process, what happens to the car's kinetic energy?

(a) 4.0 s

The acceleration of the car is given by

where

v is the final velocity

u is the initial velocity

t is the time interval

For this car, we have

v = 0 (the final speed is zero since the car comes to a stop)

u = 20 m/s is the initial velocity

is the deceleration of the car

Solving the equation for t, we find the time needed to stop the car:

(b) 40 m

The stopping distance of the car can be calculated by using the equation

where

v = 0 is the final velocity

u = 20 m/s is the initial velocity

a = -5.0 m/s^2 is the acceleration of the car

d is the stopping distance

Solving the equation for d, we find

(c)

The deceleration is given by the problem, and its value is .

(d) 5000 N

The net force applied on the car is given by

where

m is the mass of the car

a is the magnitude of the acceleration

For this car, we have

m = 1000 kg is the mass

is the magnitude of the acceleration

Solving the formula, we find

(e)

The work done by the force applied by the car is

where

F is the force applied

d is the total distance covered

Here we have

F = 5000 N

d = 40 m (stopping distance)

So, the work done is

(f) The kinetic energy is converted into thermal energy

Explanation:

when the breaks are applied, the wheels stop rotating. The car slows down, as a result of the frictional forces between the brakes and the tires and between the tires and the road. Due to the presence of these frictional forces, the kinetic energy is converted into thermal energy/heat, until the kinetic energy of the car becomes zero (this occurs when the car comes to a stop, when v = 0).

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50