In 1909 robert millikan was the first to find the charge of an electron in his now-famous oil drop experiment. in the experiment tiny oil drops are sprayed into a uniform electric field between a horizontal pair of oppositely charged plates. the drops are observed with a magnifying eyepiece, and the electric field is adjusted so that the upward force q e on some negatively charged oil drops is just sufficient to balance the downward force m g of gravity. millikan accurately measured the charges on many oil drops and found the values to be whole-number multiples of 1.6 × 10−19 c — the charge of the electron. for this he won the nobel prize. if a drop of mass 5.2898 × 10−13 kg remains stationary in an electric field of 6 × 105 n/c, what is the charge on this drop? the acceleration due to gravity is 9.8 m/s 2 . answer in units of c