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Physics, 27.09.2019 08:50, lydiakegg454
When a particle of charge q moves with a velocity vβ in a magnetic field bβ , the particle is acted upon by a force fβ exerted by the magnetic field. to find the direction and magnitude of this force, follow the steps in the following tactics box. keep in mind that the right-hand rule for forces shown in step 2 gives the direction of the force on a positive charge. for a negative charge, the force will be in the opposite direction. if the magnetic field of the wire is 4.0Γ10β4 t and the electron moves at 6.0Γ106 m/s , what is the magnitude f of the force exerted on the electron? express your answer in newtons to two significant figures.
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Answers: 1
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When a particle of charge q moves with a velocity vβ in a magnetic field bβ , the particle is acted...
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