An uncharged capacitor is connected to the terminals of a 4.0 v battery, and 9.0 μc flows to the positive plate. the 4.0 v battery is then disconnected and replaced with a 5.0 v battery, with the positive and negative terminals connected in the same manner as before. part a how much additional charge flows to the positive plate? express your answer in microcoulombs.

Explanation:

At the beginning, we have:

V = 4.0 V potential difference across the capacitor

charge stored on the capacitor

Therefore, we can calculate the capacitance of the capacitor:

Later, the battery is replaced with another battery whose voltage is

V = 5.0 V

Since the capacitance of the capacitor does not change, we can calculate the new charge stored:

Since the capacitor has been connected exactly as before, we have that the charge on the positive plate has increased from to . Therefore, the additional charge that moved to the positive plate is

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