A2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 v? what is the total energy stores in the electic field? u= jwhat is the energy densityu=/m^3

1)

The capacitance of a parallel-plate capacitor is given by:

where

is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

so the area is

While the separation between the plates is

So the capacitance is

And now we can find the energy stored,which is given by:

2) 0.71 J/m^3

The magnitude of the electric field is given by

and the energy density of the electric field is given by

and using

, we find

that the claims meet official rules.

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