Suppose a charge q=+50 uc experiences a force of 0.040 n which points to the right. what is the magnitude and direction of the electric field that causes this force?

800 N/C to the right

Explanation:

The relationship between electric force, electric field and charge is

where

E is the electric field

F is the force acting on the charge

q is the charge

In this problem, we have

is the force

is the charge

Substituting into the formula, we find the electric field magnitude

Concerning the direction:

- The electric field and the force have same directions if the charge is positive

- The electric field and the force have opposite directions if the charge is negative

Here the charge is positive, so the electric field has same direction as the force: therefore, to the right.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

a, c, d, e are all applying about success strategies.