Interactive learningware 13.1 explores the approach taken in problems such as this one. a composite rod is made from stainless steel and iron and has a length of 0.241 m. the cross section of this composite rod is shown in the drawing and consists of a square within a circle. the square cross section of the steel is 3.76 cm on a side. the temperature at one end of the rod is 88.9 °c, while it is 10.2 °c at the other end. assuming that no heat exits through the cylindrical outer surface, find the total amount of heat conducted through the rod in two minutes.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

the answer is a 3.8cm

explanation:

area of focus