How does jumping into a pool change the amount of gravity acting on you?

Because of the buoyant force

Explanation:

Jumping into a pool change the amount of apparent gravity acting on a person.

Normally, for a person in free fall, the weight of the person is given by:

where m is the mass of the person and g=9.8 m/s^ is the acceleration due to gravity.

When a person is in the water, there is a buoyant force pushing the person upward. The magnitude of the buoyant force is

where

is the density of the water

V is the volume of displaced fluid

g is the acceleration due to gravity

So the net force acting on the person is

(1)

Since V corresponds to the volume of the person, we can rewrite it as

where is the density of the person. Substituting into eq.(1),

(2)

where we called

So we can further rewrite (2) as

so we see that the gravity acting on the person, g, has been modified into (g-g') due to the presence of the buoyant force.

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

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