A2-kg bowling ball rolls at a speed of 10m/s on the ground whats its ke

Explanation:

I wonder what level of physics you are taking? If this is a beginning course (which I'm going to assume) then the KE is

KE = 1/2 m v^2

KE = 1/2 * 2kg * (10 m/s)^2

KE = 100 Joules.

If you are in an upper level course and need to take into account the rotational motion, leave a note.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards