An air-track glider is attached to a spring. the glider is pulled to the right and released from rest at t=0 s. it then oscillates with a period of 2.00 s and a maximum speed of 60.0 cm/s . you may want to review (pages 391 - 393) . part a what is the amplitude of the oscillation? express your answer with the appropriate units.

0.19 m (19 cm)

Explanation:

The maximum speed in a simple harmonic motion is given by

(1)

where

A is the amplitude

is the angular frequency, which is given by

(2)

where T is the period.

By combining (1) and (2), we find

Here we know that

v = 60.0 cm/s = 0.6 m/s is the maximum speed

T = 2.00 s is the period

Substituting into the formula, we find the amplitude:

reserve is the answer

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg