Physics, 11.10.2019 19:30, mmoore36

Determine the total resistance of each of the following parallel circuits, (you can calculate the total resistance from the
voltage using ohm's law
a. a parallel circuit with a 20-ohm resistor and a 10-ohm resistor.
b. a parallel circuit with two 20-ohm resistors and a 10-ohm resistor
c. a parallel circuit with a 15-ohm light bulb and a 20-ohm resistor.
d. a parallel circuit with two 100-ohm resistors and a 20-ohm resistor.
e. a parallel circuit with a 10-ohm, 20-ohm, 100-ohm and 200-ohm resistor.

Answers: 2

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Answers

answered: upadrastakameswari

The formula to calculate the total resistance of a parallel circuit is:

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}$

Where R_1, R_2, ... R_n are the individual resistances

Let's now apply the formula to each circuit:

A. $6.67 \Omega$

A parallel circuit with a 20-ohm resistor and a 10-ohm resistor.

The equivalent resistance is:

$\frac{1}{R_T}=\frac{1}{20 \Omega}+\frac{1}{10 \Omega}=\frac{3}{20 \Omega}$

$R_T = \frac{20}{3}\Omega =6.67 \Omega$

B. $5.0 \Omega$

A parallel circuit with two 20-ohm resistors and a 10-ohm resistor

The equivalent resistance is:

$\frac{1}{R_T}=\frac{1}{20\Omega}+\frac{1}{20 \Omega}+\frac{1}{10 \Omega}=\frac{4}{20 \Omega}$

$R_T = \frac{20}{4}\Omega =5.0 \Omega$

C. $8.57 \Omega$

A parallel circuit with a 15-ohm light bulb and a 20-ohm resistor.

The equivalent resistance is:

$\frac{1}{R_T}=\frac{1}{20 \Omega}+\frac{1}{15 \Omega}=0.1167 \Omega ^{-1}$

$R_T = \frac{1}{0.1167}\Omega =8.57 \Omega$

D. $14.3 \Omega$

A parallel circuit with two 100-ohm resistors and a 20-ohm resistor.

The equivalent resistance is:

$\frac{1}{R_T}=\frac{1}{20\Omega}+\frac{1}{100 \Omega}+\frac{1}{100 \Omega}=\frac{7}{100 \Omega}$

$R_T = \frac{100}{7}\Omega =14.3 \Omega$

E. $6.1 \Omega$

A parallel circuit with a 10-ohm, 20-ohm, 100-ohm and 200-ohm resistor.

The equivalent resistance is:

$\frac{1}{R_T}=\frac{1}{10\Omega}+\frac{1}{20 \Omega}+\frac{1}{100 \Omega}+\frac{1}{200 \Omega}=\frac{33}{200 \Omega}$

$R_T = \frac{200}{33}\Omega =6.1 \Omega$

answered: mendezmarco2004

(A) The total resistance for parallel circuit with a 20-ohm resistor and a 10-ohm resistor is 6.67 ohms.

(B) The total resistance for parallel circuit with two 20-ohm resistor and a 10-ohm resistor is 5 ohms.

(D) The total resistance for parallel circuit with a 10-ohm, a 20-ohm, 100-ohm and 200-ohm resistor is 6.06 ohms.

(E) The total resistance for parallel circuit with a 10-ohm, a 20-ohm, 100-ohm and 200-ohm resistor is 6.06 ohms.

The total resistance for the parallel combination of resistors is given as

$\dfrac{1}{R_{total}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+...........................+\dfrac{1}{R_{n}}$

And the total resistance for the series combination of resistors is,

$R_{total}=R_{1}+R_{2}+................................+R_{n}$

(A)

For parallel circuit of 20-ohm and 10-ohm resistors, the total resistance is,

$\dfrac{1}{R_{total}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}\\\dfrac{1}{R_{total}}=\dfrac{1}{20}+\dfrac{1}{10}\\R_{total}=\dfrac{20 \times 10}{20+10}\\R_{total}=6.67 \;\rm ohms$

Thus, the total resistance for parallel circuit with a 20-ohm resistor and a 10-ohm resistor is 6.67 ohms.

(B)

For parallel circuit with two 20-ohm and a 10-ohm resistor, the total resistance is,

$\dfrac{1}{R_{total}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}\\\dfrac{1}{R_{total}}=\dfrac{1}{20}+\dfrac{1}{20}+\dfrac{1}{10}\\R_{total}=\dfrac{20}{4}\\R_{total}=5 \;\rm ohms$

Thus, the total resistance for parallel circuit with two 20-ohm resistor and a 10-ohm resistor is 5 ohms.

(C)

For parallel circuit with a 15-ohm light bulb and a 20-ohm resistor, the total resistance is,

$\dfrac{1}{R_{total}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}\\\dfrac{1}{R_{total}}=\dfrac{1}{15}+\dfrac{1}{20}\\R_{total}=\dfrac{15 \times 20}{15+20}\\R_{total}=8.57 \;\rm ohms$

Thus, the total resistance for parallel circuit with a 15-ohm light bulb and a 20-ohm resistor is 8.57 ohms.

(D)

For parallel circuit with two 100-ohm and a 20-ohm resistor, the total resistance is,

$\dfrac{1}{R_{total}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}\\\dfrac{1}{R_{total}}=\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{20}\\R_{total}=\dfrac{100}{7}\\R_{total}=14.28 \;\rm ohms$

Thus, the total resistance for parallel circuit with two 100-ohm and a 20-ohm resistor is 14.28 ohms.

(E)

For parallel circuit with a 10-ohm, a 20-ohm, 100-ohm and 200-ohm resistor, the total resistance is,

$\dfrac{1}{R_{total}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}+\dfrac{1}{R_{4}}\\\dfrac{1}{R_{total}}=\dfrac{1}{10}+\dfrac{1}{20}+\dfrac{1}{100}+\dfrac{1}{200}\\R_{total}=\dfrac{200}{33}\\R_{total}=6.06 \;\rm ohms$

Thus, the total resistance for parallel circuit with a 10-ohm, a 20-ohm, 100-ohm and 200-ohm resistor is 6.06 ohms.

Learn more about parallel connection of resistances here:

link

answered: Guest

The reflection of the candle in the concave mirror formed an upside-down virtual image that is smaller than the candle.in other words. the answer is the third option, c

answered: Guest

Answer///air resistance,drag;

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Determine the total resistance of each of the following parallel circuits, (you can calculate the to...