Amotor attached to a 120 v/60 hz power line draws an 8.40 a current. its average energy dissipation is 850 w. how much series capacitance needs to be added to increase the power factor to 1.0?

The series capacitance to be added to increase the power factor is : 345 μF

Given data :

Power line voltage ( V ) = 120 V

Frequency = 60 Hz

Current drawn by power line ( I ) = 8.40 A

Average energy dissipation ( P ) = 850 W

power factor = 1

Determine the value of  series capacitance needed to increase the power factor to 1

we will apply the formulae below

first step : calculate the value of the phase angle

= cos⁻¹  

   = cos⁻¹ ( 850 / ( 120 * 8.4 ) )

   = 32.5°

Final step : Determine the series Capacitance

Series Capacitance ( C ) =

Therefore C =

                    = 345 * 10⁻⁶ F = 345 μF

Hence we can conclude that The series capacitance to be added to increase the power factor is : 345 μF

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