The k-shell ionization energy of iron is 8500 ev, and it's l-shell ionization energy is 2125 ev. what is the wavelength of kalpha x-rays emmited by iron?

Explanation:

First of all, we need to calculate the energy of the x-ray photon emitted during the transition from K-shell to L-shell, and this energy is equal to the difference in energy between the two levels:

Converting into Joules,

Now we know that the energy of the photon is related to its wavelength by:

where

h is the Planck constant

c is the speed of light

is the wavelength

Re-arranging the equation for , we find

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.