One uniform sphere of matter has a radius of 0.50 m and a mass of 65 kg. a second uniform sphere has a radius of 0.80 m and a mass of 87 kg. the surfaces of the spheres are 1.20 m apart, as measured on a line drawn between the centers of the spheres. what is the magnitude of the gravitational force that each sphere exerts on the other?

We have that for the Question, it can be said that the magnitude of the gravitational force that each sphere exerts on the other is

F=6.1*10^{-8}N

From the question we are told

One uniform sphere of matter has a radius of 0.50 m and a mass of 65 kg. A second uniform sphere has a radius of 0.80 m and a mass of 87 kg. The surfaces of the spheres are 1.20 m apart, as measured on a line drawn between the centers of the spheres. What is the magnitude of the gravitational force that each sphere exerts on the other?

Generally the equation for the Gravitational force  is mathematically given as

F=6.1*10^{-8}N

Therefore

the magnitude of the gravitational force that each sphere exerts on the other is

F=6.1*10^{-8}N

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Explanation:

The magnitude of the gravitational force between the two spheres is given by:

where

G is the gravitational constant

m1 , m2 are the masses of the two spheres

r is the distance between the centres of the two spheres

Here we have:

m1 = 65 kg is the mass of the first sphere

m2 = 87 kg is the mass of the second sphere

the distance between the centres of the two spheres is equal to the sum of the radius of each sphere and the distance between the surfaces:

r = 0.50 m + 0.80 m + 1.20 m = 2.50 m

Substituting the numbers into the formula, we find:

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation:

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.