A10.0 v battery is connected across two resistors in series. one resistor has resistance of 840.0 ω and the other has resistance of 590.0 ω. what is the voltage drop across the 590.0 ω resistor?

Explanation:

There are a couple of ways you could do this.

The easiest is to use E*R1/(R1 + R2)

So the result would be

E_590 = 10 * 590/(590 + 840)

E_590 = 10 * 590/ (1430)

E_590 = 4.13 volts rounded.

You could do this a slightly longer way.

R = 1430 (total ohms in series.

E = 10 volts

I = ???

I = E/R

I = 10 / 1430

I = 0.00699

Now use this current to figure out the voltage drop.

E = I * R

I = 0.00699 amps

R = 590 ohms

E = 0.00699 * 590

E = 4.13 volts

Pick the way of doing it you like best.

it becomes positively charged by charging it

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles