Abullet of mass 0.016 kg traveling horizontally at a speed of 280 m/s embeds itself in a block of mass 3 kg that is sitting at rest on a nearly frictionless surface. (a) what is the speed of the block after the bullet embeds itself in the block? vf= m/s (b) calculate the total translational kinetic energy before and after the collision. ktrans, i= j ktrans, f= j (c) compare the two results and explain why there is a difference. the internal energy of the block-bullet system has increased. the energy principle isn't valid for an inelastic collision. some of the momentum is lost in an inelastic collision.

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

where

m = 0.016 kg is the mass of the bullet

is the initial velocity of the bullet

M = 3 kg is the mass of the block

is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: