Alight beam travels at 1.94×108 in quartz. the wavelength of the light in quartz is 355 .part awhat is the index of refraction of quartz at this wavelength? part bif this same light travels through air, what is its wavelength there?

A) 1.55

The speed of light in a medium is given by:

where

is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

where

is the wavelenght in quartz

is the wavelength in air

n is the refractive index

For the light in this problem, we have

Therefore, we can re-arrange the equation to find , the wavelength in air:

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

reserve is the answer