Aball is thrown horizontally at a height of 2.2 meters at a velocity of 65m/s off a cliff. assume no air resistance. how long until the ball reaches the ground?

We have that A ball is thrown horizontally at a height of 2.2 meters at a velocity of 65m/s off a cliff. Assuming no air resistance will take t to reach the ground

t=0.670sec

From the question we are told that

A ball is thrown horizontally at a height of 2.2 meters

a velocity of 65m/s off a cliff

Generally the equation for the Time is mathematically given as

s=ut+1/2gt^2

Therefore

Therefore

A ball is thrown horizontally at a height of 2.2 meters at a velocity of 65m/s off a cliff. Assuming no air resistance will take t to reach the ground

t=0.670sec

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The horizontal motion has no effect on the vertical drop.

From a drop, the distance the ball falls in 'T' seconds is

D = 4.9 T^2

so

2.2 = 4.9 T^2

T^2 = 2.2/4.9

T^2 = 0.449 sec^2

T = 0.67 second

i think the answer is a, hope this is right, that would be my best guess.

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explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."